a^2-49a=0

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Solution for a^2-49a=0 equation: 



a^2-49a=0

a = 1; b = -49; c = 0;
Δ = b2-4ac
Δ = -492-4·1·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-49}{2*1}=\frac{0}{2}
=0
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+49}{2*1}=\frac{98}{2}
=49
$

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